Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Volume of a Pyramid length 73 inches by width 96 in by height 32 in is 74752.0 inches3

The Volume of a Pyramid is equal to the 1/3 times length(1) times the width(w) times the height(h). If the Pyramid has a length 73 inches by width 96 in by height 32 in is 74752.0 inches3.


    Volume of Cone 73 in by 96 in by 32 in in other units

Value unit
1.8987008 km3
1.1798009 mi3
1898.7008 m3
6229.3333333 ft3
74752.0 in3
2076.4444444 yd3
189870.08 cm3
1898700.8 mm3

Steps:

The volume of a pyramid is equal to $1\above 1pt3$ *length * width * height

Substitute the values of the length l = 73 in , the width w = 96 in , and the height h = 32 in into the formula

$1\above 1pt3$ * (73 in * 96 in * 32 in)

Multiply 73 in and 96 in

$1\above 1pt3$ * 7008.0 in2 * 32 in

Multiply 7008.0 in2 and 32 in

Divide 224256.0 in by number 3

Volume = 74752.0 in3

∴ Volume of a Pyramid length 73 in , width 96 in and height 32 in is 74752.0 in2