Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Volume of a Pyramid length 40 foot by width 98 ft by height 72 ft is 94080.0 foot3

The Volume of a Pyramid is equal to the 1/3 times length(1) times the width(w) times the height(h). If the Pyramid has a length 40 foot by width 98 ft by height 72 ft is 94080.0 foot3.


    Volume of Cone 40 ft by 98 ft by 72 ft in other units

Value unit
28.675584 km3
17.8182261 mi3
28675.584 m3
94080.0 ft3
1128960.0 in3
31360.0 yd3
2867558.4 cm3
28675584.0 mm3

Steps:

The volume of a pyramid is equal to $1\above 1pt3$ *length * width * height

Substitute the values of the length l = 40 ft , the width w = 98 ft , and the height h = 72 ft into the formula

$1\above 1pt3$ * (40 ft * 98 ft * 72 ft)

Multiply 40 ft and 98 ft

$1\above 1pt3$ * 3920.0 ft2 * 72 ft

Multiply 3920.0 ft2 and 72 ft

Divide 282240.0 ft by number 3

Volume = 94080.0 ft3

∴ Volume of a Pyramid length 40 ft , width 98 ft and height 72 ft is 94080.0 ft2