Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Volume of a Pyramid length 40 foot by width 98 ft by height 71 ft is 92773.3333333 foot3

The Volume of a Pyramid is equal to the 1/3 times length(1) times the width(w) times the height(h). If the Pyramid has a length 40 foot by width 98 ft by height 71 ft is 92773.3333333 foot3.


    Volume of Cone 40 ft by 98 ft by 71 ft in other units

Value unit
28.277312 km3
17.5707507 mi3
28277.312 m3
92773.3333333 ft3
1113279.9999996 in3
30924.4444444 yd3
2827731.199999 cm3
28277311.9999898 mm3

Steps:

The volume of a pyramid is equal to $1\above 1pt3$ *length * width * height

Substitute the values of the length l = 40 ft , the width w = 98 ft , and the height h = 71 ft into the formula

$1\above 1pt3$ * (40 ft * 98 ft * 71 ft)

Multiply 40 ft and 98 ft

$1\above 1pt3$ * 3920.0 ft2 * 71 ft

Multiply 3920.0 ft2 and 71 ft

Divide 278320.0 ft by number 3

Volume = 92773.3333333 ft3

∴ Volume of a Pyramid length 40 ft , width 98 ft and height 71 ft is 92773.3333333 ft2