Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Volume of a Pyramid length 40 foot by width 98 ft by height 68 ft is 88853.3333333 foot3

The Volume of a Pyramid is equal to the 1/3 times length(1) times the width(w) times the height(h). If the Pyramid has a length 40 foot by width 98 ft by height 68 ft is 88853.3333333 foot3.


    Volume of Cone 40 ft by 98 ft by 68 ft in other units

Value unit
27.082496 km3
16.8283247 mi3
27082.496 m3
88853.3333333 ft3
1066239.9999996 in3
29617.7777778 yd3
2708249.599999 cm3
27082495.9999898 mm3

Steps:

The volume of a pyramid is equal to $1\above 1pt3$ *length * width * height

Substitute the values of the length l = 40 ft , the width w = 98 ft , and the height h = 68 ft into the formula

$1\above 1pt3$ * (40 ft * 98 ft * 68 ft)

Multiply 40 ft and 98 ft

$1\above 1pt3$ * 3920.0 ft2 * 68 ft

Multiply 3920.0 ft2 and 68 ft

Divide 266560.0 ft by number 3

Volume = 88853.3333333 ft3

∴ Volume of a Pyramid length 40 ft , width 98 ft and height 68 ft is 88853.3333333 ft2