Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Volume of a Pyramid length 39 inches by width 97 in by height 19 in is 23959.0 inches3

The Volume of a Pyramid is equal to the 1/3 times length(1) times the width(w) times the height(h). If the Pyramid has a length 39 inches by width 97 in by height 19 in is 23959.0 inches3.


    Volume of Cone 39 in by 97 in by 19 in in other units

Value unit
0.6085586 km3
0.3781417 mi3
608.5586 m3
1996.5833333 ft3
23959.0 in3
665.5277778 yd3
60855.86 cm3
608558.6 mm3

Steps:

The volume of a pyramid is equal to $1\above 1pt3$ *length * width * height

Substitute the values of the length l = 39 in , the width w = 97 in , and the height h = 19 in into the formula

$1\above 1pt3$ * (39 in * 97 in * 19 in)

Multiply 39 in and 97 in

$1\above 1pt3$ * 3783.0 in2 * 19 in

Multiply 3783.0 in2 and 19 in

Divide 71877.0 in by number 3

Volume = 23959.0 in3

∴ Volume of a Pyramid length 39 in , width 97 in and height 19 in is 23959.0 in2