Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Volume of a Pyramid length 10 foot by width 93 ft by height 28 ft is 8680.0 foot3

The Volume of a Pyramid is equal to the 1/3 times length(1) times the width(w) times the height(h). If the Pyramid has a length 10 foot by width 93 ft by height 28 ft is 8680.0 foot3.


    Volume of Cone 10 ft by 93 ft by 28 ft in other units

Value unit
2.645664 km3
1.6439435 mi3
2645.664 m3
8680.0 ft3
104160.0 in3
2893.3333333 yd3
264566.4 cm3
2645664.0 mm3

Steps:

The volume of a pyramid is equal to $1\above 1pt3$ *length * width * height

Substitute the values of the length l = 10 ft , the width w = 93 ft , and the height h = 28 ft into the formula

$1\above 1pt3$ * (10 ft * 93 ft * 28 ft)

Multiply 10 ft and 93 ft

$1\above 1pt3$ * 930.0 ft2 * 28 ft

Multiply 930.0 ft2 and 28 ft

Divide 26040.0 ft by number 3

Volume = 8680.0 ft3

∴ Volume of a Pyramid length 10 ft , width 93 ft and height 28 ft is 8680.0 ft2