Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of bottom radius(r)

Enter the Value of height(h)


Surface Area of Cylinder Base Radius 18 inches by height 64 inches is 9269.28 inches2

The Surface Area of a Cylinder is equal to the sum of the areas of the bases each having an area of π ⋅ r2 , plus the area of the side. The area of the side is equal to the area of a rectangle with length 2 π r (the circumference of the base) times the height. Surface Area of Cylinder Base Radius 18 inches by height 64 inches is9269.28 inches2.


    Surface Area of a Cylinder 18 in by 64 in in other units

Value unit
0.2354397 km2
0.1462958 mi2
235.439712 m2
772.44 ft2
9269.28 in2
257.48 yd2
23543.9712 cm2
235439.712 mm2

Steps:

Given that Base radius(r) = 18 in and height(h) = 64 in

The Surface Area of Cylinder = 2π .(Radius)2 + 2π .(Radius) . (Height)

Substitute the values of the radius r = 18 in and height h = 64 in into the formula. Pi (π) is approximately equal to 3.14 .

2 . (π) . (182) in2 + 2 .(π) . (18) in . (64.0) in

Raise 18.0 in to the power of 2.

2 .(π) . (324.0) in2 + 2 . (π) . (18.0) in . (64.0) in

Multiply 324.0 in2 by 2

648.0 in2 . π + 2 .(π) . 18.0 in . 64.0 in

Multiply 18.0 in and 64.0 in

648.0 in . π + 1152.0 in2 . π . 2

Multiply 1152.0 in2 and 2

648.0 in2 . π + 2304.0 in2 . π

Add 648.0 . π in2 and 2304.0 . π in2

The result can be shown in multiple forms.

Exact Form

2952.0 . π in2

∴ Surface Area of Cylinder 18.0 in by 64.0 in is 2952.0 . π in2

Decimal Form

9269.28 in2

∴ Surface Area of Cylinder 18.0 in by 64.0 in is 9269.28 in2