Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of bottom radius(r)

Enter the Value of height(h)


Surface Area of Cylinder Base Radius 11 inches by height 57 inches is 4697.44 inches2

The Surface Area of a Cylinder is equal to the sum of the areas of the bases each having an area of π ⋅ r2 , plus the area of the side. The area of the side is equal to the area of a rectangle with length 2 π r (the circumference of the base) times the height. Surface Area of Cylinder Base Radius 11 inches by height 57 inches is4697.44 inches2.


    Surface Area of a Cylinder 11 in by 57 in in other units

Value unit
0.119315 km2
0.0741391 mi2
119.314976 m2
391.4533333 ft2
4697.44 in2
130.4844444 yd2
11931.4976 cm2
119314.976 mm2

Steps:

Given that Base radius(r) = 11 in and height(h) = 57 in

The Surface Area of Cylinder = 2π .(Radius)2 + 2π .(Radius) . (Height)

Substitute the values of the radius r = 11 in and height h = 57 in into the formula. Pi (π) is approximately equal to 3.14 .

2 . (π) . (112) in2 + 2 .(π) . (11) in . (57.0) in

Raise 11.0 in to the power of 2.

2 .(π) . (121.0) in2 + 2 . (π) . (11.0) in . (57.0) in

Multiply 121.0 in2 by 2

242.0 in2 . π + 2 .(π) . 11.0 in . 57.0 in

Multiply 11.0 in and 57.0 in

242.0 in . π + 627.0 in2 . π . 2

Multiply 627.0 in2 and 2

242.0 in2 . π + 1254.0 in2 . π

Add 242.0 . π in2 and 1254.0 . π in2

The result can be shown in multiple forms.

Exact Form

1496.0 . π in2

∴ Surface Area of Cylinder 11.0 in by 57.0 in is 1496.0 . π in2

Decimal Form

4697.44 in2

∴ Surface Area of Cylinder 11.0 in by 57.0 in is 4697.44 in2