Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of base radius(r)

Enter the Value of height(h)


If the cone Radius 21 inches by height 67 inches is 6014.6484384 inches2.


The surface area of a cone is equal to the area of the base plus the area of the cone. If the cone Radius 21 inches by height 67 inches is 6014.6484384 inches2.


    Surface Area of a Cone 21 in by 67 in in other units

Value unit
0.1527721 km2
0.0949284 mi2
152.7720703 m2
501.2207032 ft2
6014.6484384 in2
167.0735677 yd2
15277.2070335 cm2
152772.0703354 mm2

Steps:

Given that Base radius(r) = 21 in and height(h) = 67 in

Surface Area of a Cone = $(π⋅(Radius))$⋅($(Radius)$ + $\sqrt{(Radius)^2+(Height)^2}$)

Substitute the values of the radius r = 21 in and height h = 67 in into the formula. Pi (π) is approximately equal to 3.14 .

$(π⋅(21))$⋅ $(21$ + $\sqrt{(21)^2 + (67)^2})$

Move 21 to the left of π.

$(21π)$⋅$ (21$ + $\sqrt{(21)^2 + (67)^2}$

Simplify each term

Raise 21 in to the power of 2 and 67 to the power of 2

$(21π)$⋅$ (21$ + $\sqrt{(441.0) + (4489.0)}$ in

Add 441.0 in and 4489.0 in

$(21π)$ in⋅$ (21$ + $\sqrt{(4930.0)}$ in

Multipy 21π in and 21 in

441.0π in + (21π . $\sqrt4930.0$)in

Put the value of $\sqrt4930.0$ = 70.2139587 in formula

441.0π in + (21π . 70.2139587) in

Mulitply the 21π and 70.2139587

441.0π in + (1474.4931332π)

Add 441.0π in and 1474.4931332π in

The result can be shown in multiple forms

Exact Form

Area = 1915.4931332π in

∴ Surface Area of Cone 21 in by 67 in is 1915.4931332π in2

Decimal Form

6014.6484384 in2

∴ Surface Area of Cylinder 21 in by 67 in is 6014.6484384 in2