Surface area of a Pyramid 98 meters by 34 meters by 94 meters Calculator
The Surface Area of Pyramid 98 meters by width 34 meters by height 94 meters is 16297.5972293 meters2.
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 98 meters by width 34 meters by height 94 meters is 16297.5972293 meters2.
Surface Area of a Pyramid 98 m by 34 m by 94 m in other units
Value | unit |
---|---|
16.2975972 | km2 |
10.1268826 | mi2 |
16297.5972293 | m2 |
53469.8071827 | ft2 |
641637.6861929 | in2 |
17823.2690609 | yd2 |
1629759.72293 | cm2 |
16297597.2293 | mm2 |
Steps:
The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$
Substitute the values of the length l =98 , the width w =34 , and the height h =94 into the formula for surface area of a pyramid
A=($98 \cdot34+98$$\sqrt{(\frac{34}{2})^2+(94)^2}$$+34$$\sqrt{(\frac{98}{2})^2+(94)^2}$) m
Simplify each term.
Multiply 98 m by 34 m
A = $3332.0 + 98$$\sqrt{(\frac{34}{2})^2+(94)^2}$$+34$$\sqrt{(\frac{98}{2})^2+(94)^2}$
Square root of $\sqrt{(\frac{34}{2})^2+(94)^2}$ is 95.5248659
Put The values in Area Formula:
A= $3332.0 + 98 \cdot 95.5248659 + 34$$\sqrt{(\frac{98}{2})^2 + (94)^2}$
Square Root of $\sqrt{(\frac{98}{2})^2+(94)^2}$ is 106.0047169
Put The values in Area Formula:
A= 3332.0 + 98 x 95.5248659 + 34 x 106.0047169
Multiply 98 and 95.5248659
A= 3332.0 + 9361.4368555 + 34 x 106.0047169
Multiply 34 and 106.0047169
A= 3332.0 + 9361.4368555 + 3604.1603738
Add 3332.0 and 9361.4368555
A=12693.4368555 + 3604.1603738
A= 16297.5972293 m2
∴ The Surface Area of Pyramid length 98 m , width 34 m and height 94 m is 16297.5972293 m2