Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 98 meters by width 34 meters by height 94 meters is 16297.5972293 meters2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 98 meters by width 34 meters by height 94 meters is 16297.5972293 meters2.


    Surface Area of a Pyramid 98 m by 34 m by 94 m in other units

Value unit
16.2975972 km2
10.1268826 mi2
16297.5972293 m2
53469.8071827 ft2
641637.6861929 in2
17823.2690609 yd2
1629759.72293 cm2
16297597.2293 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =98 , the width w =34 , and the height h =94 into the formula for surface area of a pyramid

A=($98 \cdot34+98$$\sqrt{(\frac{34}{2})^2+(94)^2}$$+34$$\sqrt{(\frac{98}{2})^2+(94)^2}$) m

Simplify each term.

Multiply 98 m by 34 m

A = $3332.0 + 98$$\sqrt{(\frac{34}{2})^2+(94)^2}$$+34$$\sqrt{(\frac{98}{2})^2+(94)^2}$

Square root of $\sqrt{(\frac{34}{2})^2+(94)^2}$ is 95.5248659

Put The values in Area Formula:

A= $3332.0 + 98 \cdot 95.5248659 + 34$$\sqrt{(\frac{98}{2})^2 + (94)^2}$

Square Root of $\sqrt{(\frac{98}{2})^2+(94)^2}$ is 106.0047169

Put The values in Area Formula:

A= 3332.0 + 98 x 95.5248659 + 34 x 106.0047169

Multiply 98 and 95.5248659

A= 3332.0 + 9361.4368555 + 34 x 106.0047169

Multiply 34 and 106.0047169

A= 3332.0 + 9361.4368555 + 3604.1603738

Add 3332.0 and 9361.4368555

A=12693.4368555 + 3604.1603738

A= 16297.5972293 m2

∴ The Surface Area of Pyramid length 98 m , width 34 m and height 94 m is 16297.5972293 m2