Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 86 meters by width 78 meters by height 70 meters is 20007.1574682 meters2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 86 meters by width 78 meters by height 70 meters is 20007.1574682 meters2.


    Surface Area of a Pyramid 86 m by 78 m by 70 m in other units

Value unit
20.0071575 km2
12.4319022 mi2
20007.1574682 m2
65640.2804075 ft2
787683.3648898 in2
21880.0934692 yd2
2000715.74682 cm2
20007157.4682 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =86 , the width w =78 , and the height h =70 into the formula for surface area of a pyramid

A=($86 \cdot78+86$$\sqrt{(\frac{78}{2})^2+(70)^2}$$+78$$\sqrt{(\frac{86}{2})^2+(70)^2}$) m

Simplify each term.

Multiply 86 m by 78 m

A = $6708.0 + 86$$\sqrt{(\frac{78}{2})^2+(70)^2}$$+78$$\sqrt{(\frac{86}{2})^2+(70)^2}$

Square root of $\sqrt{(\frac{78}{2})^2+(70)^2}$ is 80.1311425

Put The values in Area Formula:

A= $6708.0 + 86 \cdot 80.1311425 + 78$$\sqrt{(\frac{86}{2})^2 + (70)^2}$

Square Root of $\sqrt{(\frac{86}{2})^2+(70)^2}$ is 82.1522976

Put The values in Area Formula:

A= 6708.0 + 86 x 80.1311425 + 78 x 82.1522976

Multiply 86 and 80.1311425

A= 6708.0 + 6891.2782559 + 78 x 82.1522976

Multiply 78 and 82.1522976

A= 6708.0 + 6891.2782559 + 6407.8792123

Add 6708.0 and 6891.2782559

A=13599.2782559 + 6407.8792123

A= 20007.1574682 m2

∴ The Surface Area of Pyramid length 86 m , width 78 m and height 70 m is 20007.1574682 m2