Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 83 yards by width 52 yards by height 42 yards is 11486.2102474 yards2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 83 yards by width 52 yards by height 42 yards is 11486.2102474 yards2.


    Surface Area of a Pyramid 83 yd by 52 yd by 42 yd in other units

Value unit
10.5029907 km2
6.526272 mi2
10502.9906502 m2
34458.6307422 ft2
413503.5689064 in2
11486.2102474 yd2
1050299.0650223 cm2
10502990.6502226 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =83 , the width w =52 , and the height h =42 into the formula for surface area of a pyramid

A=($83 \cdot52+83$$\sqrt{(\frac{52}{2})^2+(42)^2}$$+52$$\sqrt{(\frac{83}{2})^2+(42)^2}$) yd

Simplify each term.

Multiply 83 yd by 52 yd

A = $4316.0 + 83$$\sqrt{(\frac{52}{2})^2+(42)^2}$$+52$$\sqrt{(\frac{83}{2})^2+(42)^2}$

Square root of $\sqrt{(\frac{52}{2})^2+(42)^2}$ is 49.3963561

Put The values in Area Formula:

A= $4316.0 + 83 \cdot 49.3963561 + 52$$\sqrt{(\frac{83}{2})^2 + (42)^2}$

Square Root of $\sqrt{(\frac{83}{2})^2+(42)^2}$ is 59.0444748

Put The values in Area Formula:

A= 4316.0 + 83 x 49.3963561 + 52 x 59.0444748

Multiply 83 and 49.3963561

A= 4316.0 + 4099.8975597 + 52 x 59.0444748

Multiply 52 and 59.0444748

A= 4316.0 + 4099.8975597 + 3070.3126877

Add 4316.0 and 4099.8975597

A=8415.8975597 + 3070.3126877

A= 11486.2102474 yd2

∴ The Surface Area of Pyramid length 83 yd , width 52 yd and height 42 yd is 11486.2102474 yd2