Surface area of a Pyramid 75 inches by 96 inches by 32 inches Calculator

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 75 inches by width 96 inches by height 32 inches is 16259.2278534 inches².

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =75 , the width w =96 , and the height h =32 into the formula for surface area of a pyramid

A=($75 \cdot96+75$$\sqrt{(\frac{96}{2})^2+(32)^2}$$+96$$\sqrt{(\frac{75}{2})^2+(32)^2}$) in

Simplify each term.

Multiply 75 in by 96 in

A = $7200.0 + 75$$\sqrt{(\frac{96}{2})^2+(32)^2}$$+96$$\sqrt{(\frac{75}{2})^2+(32)^2}$

Square root of $\sqrt{(\frac{96}{2})^2+(32)^2}$ is 57.6888204

Put The values in Area Formula:

A= $7200.0 + 75 \cdot 57.6888204 + 96$$\sqrt{(\frac{75}{2})^2 + (32)^2}$

Square Root of $\sqrt{(\frac{75}{2})^2+(32)^2}$ is 49.2975659

Put The values in Area Formula:

A= 7200.0 + 75 x 57.6888204 + 96 x 49.2975659

Multiply 75 and 57.6888204

A= 7200.0 + 4326.6615306 + 96 x 49.2975659

Multiply 96 and 49.2975659

A= 7200.0 + 4326.6615306 + 4732.5663228

Add 7200.0 and 4326.6615306

A=11526.6615306 + 4732.5663228

A= 16259.2278534 in²

∴ The Surface Area of Pyramid length 75 in , width 96 in and height 32 in is 16259.2278534 in²