Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 71 inches by width 96 inches by height 37 inches is 16041.4913308 inches2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 71 inches by width 96 inches by height 37 inches is 16041.4913308 inches2.


    Surface Area of a Pyramid 71 in by 96 in by 37 in in other units

Value unit
0.4074539 km2
0.2531807 mi2
407.4538798 m2
1336.7909442 ft2
16041.4913308 in2
445.5969814 yd2
40745.3879802 cm2
407453.8798023 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =71 , the width w =96 , and the height h =37 into the formula for surface area of a pyramid

A=($71 \cdot96+71$$\sqrt{(\frac{96}{2})^2+(37)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(37)^2}$) in

Simplify each term.

Multiply 71 in by 96 in

A = $6816.0 + 71$$\sqrt{(\frac{96}{2})^2+(37)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(37)^2}$

Square root of $\sqrt{(\frac{96}{2})^2+(37)^2}$ is 60.6052803

Put The values in Area Formula:

A= $6816.0 + 71 \cdot 60.6052803 + 96$$\sqrt{(\frac{71}{2})^2 + (37)^2}$

Square Root of $\sqrt{(\frac{71}{2})^2+(37)^2}$ is 51.2762128

Put The values in Area Formula:

A= 6816.0 + 71 x 60.6052803 + 96 x 51.2762128

Multiply 71 and 60.6052803

A= 6816.0 + 4302.9749012 + 96 x 51.2762128

Multiply 96 and 51.2762128

A= 6816.0 + 4302.9749012 + 4922.5164296

Add 6816.0 and 4302.9749012

A=11118.9749012 + 4922.5164296

A= 16041.4913308 in2

∴ The Surface Area of Pyramid length 71 in , width 96 in and height 37 in is 16041.4913308 in2