Surface area of a Pyramid 71 inches by 96 inches by 37 inches Calculator
The Surface Area of Pyramid 71 inches by width 96 inches by height 37 inches is 16041.4913308 inches2.
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 71 inches by width 96 inches by height 37 inches is 16041.4913308 inches2.
Surface Area of a Pyramid 71 in by 96 in by 37 in in other units
Value | unit |
---|---|
0.4074539 | km2 |
0.2531807 | mi2 |
407.4538798 | m2 |
1336.7909442 | ft2 |
16041.4913308 | in2 |
445.5969814 | yd2 |
40745.3879802 | cm2 |
407453.8798023 | mm2 |
Steps:
The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$
Substitute the values of the length l =71 , the width w =96 , and the height h =37 into the formula for surface area of a pyramid
A=($71 \cdot96+71$$\sqrt{(\frac{96}{2})^2+(37)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(37)^2}$) in
Simplify each term.
Multiply 71 in by 96 in
A = $6816.0 + 71$$\sqrt{(\frac{96}{2})^2+(37)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(37)^2}$
Square root of $\sqrt{(\frac{96}{2})^2+(37)^2}$ is 60.6052803
Put The values in Area Formula:
A= $6816.0 + 71 \cdot 60.6052803 + 96$$\sqrt{(\frac{71}{2})^2 + (37)^2}$
Square Root of $\sqrt{(\frac{71}{2})^2+(37)^2}$ is 51.2762128
Put The values in Area Formula:
A= 6816.0 + 71 x 60.6052803 + 96 x 51.2762128
Multiply 71 and 60.6052803
A= 6816.0 + 4302.9749012 + 96 x 51.2762128
Multiply 96 and 51.2762128
A= 6816.0 + 4302.9749012 + 4922.5164296
Add 6816.0 and 4302.9749012
A=11118.9749012 + 4922.5164296
A= 16041.4913308 in2
∴ The Surface Area of Pyramid length 71 in , width 96 in and height 37 in is 16041.4913308 in2