Surface area of a Pyramid 71 inches by 96 inches by 34 inches Calculator
The Surface Area of Pyramid 71 inches by width 96 inches by height 34 inches is 15711.2604218 inches2.
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 71 inches by width 96 inches by height 34 inches is 15711.2604218 inches2.
Surface Area of a Pyramid 71 in by 96 in by 34 in in other units
Value | unit |
---|---|
0.399066 | km2 |
0.2479687 | mi2 |
399.0660147 | m2 |
1309.2717018 | ft2 |
15711.2604218 | in2 |
436.4239006 | yd2 |
39906.6014714 | cm2 |
399066.0147137 | mm2 |
Steps:
The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$
Substitute the values of the length l =71 , the width w =96 , and the height h =34 into the formula for surface area of a pyramid
A=($71 \cdot96+71$$\sqrt{(\frac{96}{2})^2+(34)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(34)^2}$) in
Simplify each term.
Multiply 71 in by 96 in
A = $6816.0 + 71$$\sqrt{(\frac{96}{2})^2+(34)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(34)^2}$
Square root of $\sqrt{(\frac{96}{2})^2+(34)^2}$ is 58.8217647
Put The values in Area Formula:
A= $6816.0 + 71 \cdot 58.8217647 + 96$$\sqrt{(\frac{71}{2})^2 + (34)^2}$
Square Root of $\sqrt{(\frac{71}{2})^2+(34)^2}$ is 49.1553659
Put The values in Area Formula:
A= 6816.0 + 71 x 58.8217647 + 96 x 49.1553659
Multiply 71 and 58.8217647
A= 6816.0 + 4176.3452922 + 96 x 49.1553659
Multiply 96 and 49.1553659
A= 6816.0 + 4176.3452922 + 4718.9151296
Add 6816.0 and 4176.3452922
A=10992.3452922 + 4718.9151296
A= 15711.2604218 in2
∴ The Surface Area of Pyramid length 71 in , width 96 in and height 34 in is 15711.2604218 in2