Surface area of a Pyramid 71 inches by 96 inches by 33 inches Calculator

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 71 inches by width 96 inches by height 33 inches is 15604.7418903 inches².

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =71 , the width w =96 , and the height h =33 into the formula for surface area of a pyramid

A=($71 \cdot96+71$$\sqrt{(\frac{96}{2})^2+(33)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(33)^2}$) in

Simplify each term.

Multiply 71 in by 96 in

A = $6816.0 + 71$$\sqrt{(\frac{96}{2})^2+(33)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(33)^2}$

Square root of $\sqrt{(\frac{96}{2})^2+(33)^2}$ is 58.2494635

Put The values in Area Formula:

A= $6816.0 + 71 \cdot 58.2494635 + 96$$\sqrt{(\frac{71}{2})^2 + (33)^2}$

Square Root of $\sqrt{(\frac{71}{2})^2+(33)^2}$ is 48.4690623

Put The values in Area Formula:

A= 6816.0 + 71 x 58.2494635 + 96 x 48.4690623

Multiply 71 and 58.2494635

A= 6816.0 + 4135.7119097 + 96 x 48.4690623

Multiply 96 and 48.4690623

A= 6816.0 + 4135.7119097 + 4653.0299806

Add 6816.0 and 4135.7119097

A=10951.7119097 + 4653.0299806

A= 15604.7418903 in²

∴ The Surface Area of Pyramid length 71 in , width 96 in and height 33 in is 15604.7418903 in²