Surface area of a Pyramid 71 inches by 96 inches by 32 inches Calculator

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 71 inches by width 96 inches by height 32 inches is 15500.1137421 inches².

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =71 , the width w =96 , and the height h =32 into the formula for surface area of a pyramid

A=($71 \cdot96+71$$\sqrt{(\frac{96}{2})^2+(32)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(32)^2}$) in

Simplify each term.

Multiply 71 in by 96 in

A = $6816.0 + 71$$\sqrt{(\frac{96}{2})^2+(32)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(32)^2}$

Square root of $\sqrt{(\frac{96}{2})^2+(32)^2}$ is 57.6888204

Put The values in Area Formula:

A= $6816.0 + 71 \cdot 57.6888204 + 96$$\sqrt{(\frac{71}{2})^2 + (32)^2}$

Square Root of $\sqrt{(\frac{71}{2})^2+(32)^2}$ is 47.7938281

Put The values in Area Formula:

A= 6816.0 + 71 x 57.6888204 + 96 x 47.7938281

Multiply 71 and 57.6888204

A= 6816.0 + 4095.9062489 + 96 x 47.7938281

Multiply 96 and 47.7938281

A= 6816.0 + 4095.9062489 + 4588.2074931

Add 6816.0 and 4095.9062489

A=10911.9062489 + 4588.2074931

A= 15500.1137421 in²

∴ The Surface Area of Pyramid length 71 in , width 96 in and height 32 in is 15500.1137421 in²