Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 45 foot by width 98 foot by height 67 foot is 15071.6251659 foot2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 45 foot by width 98 foot by height 67 foot is 15071.6251659 foot2.


    Surface Area of a Pyramid 45 ft by 98 ft by 67 ft in other units

Value unit
4.5938314 km2
2.8544816 mi2
4593.8313506 m2
15071.6251659 ft2
180859.5019908 in2
5023.8750553 yd2
459383.1350566 cm2
4593831.3505663 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =45 , the width w =98 , and the height h =67 into the formula for surface area of a pyramid

A=($45 \cdot98+45$$\sqrt{(\frac{98}{2})^2+(67)^2}$$+98$$\sqrt{(\frac{45}{2})^2+(67)^2}$) ft

Simplify each term.

Multiply 45 ft by 98 ft

A = $4410.0 + 45$$\sqrt{(\frac{98}{2})^2+(67)^2}$$+98$$\sqrt{(\frac{45}{2})^2+(67)^2}$

Square root of $\sqrt{(\frac{98}{2})^2+(67)^2}$ is 83.0060239

Put The values in Area Formula:

A= $4410.0 + 45 \cdot 83.0060239 + 98$$\sqrt{(\frac{45}{2})^2 + (67)^2}$

Square Root of $\sqrt{(\frac{45}{2})^2+(67)^2}$ is 70.6770826

Put The values in Area Formula:

A= 4410.0 + 45 x 83.0060239 + 98 x 70.6770826

Multiply 45 and 83.0060239

A= 4410.0 + 3735.2710745 + 98 x 70.6770826

Multiply 98 and 70.6770826

A= 4410.0 + 3735.2710745 + 6926.3540914

Add 4410.0 and 3735.2710745

A=8145.2710745 + 6926.3540914

A= 15071.6251659 ft2

∴ The Surface Area of Pyramid length 45 ft , width 98 ft and height 67 ft is 15071.6251659 ft2