Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 44 foot by width 98 foot by height 67 foot is 14875.1761338 foot2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 44 foot by width 98 foot by height 67 foot is 14875.1761338 foot2.


    Surface Area of a Pyramid 44 ft by 98 ft by 67 ft in other units

Value unit
4.5339537 km2
2.8172752 mi2
4533.9536856 m2
14875.1761338 ft2
178502.1136056 in2
4958.3920446 yd2
453395.3685582 cm2
4533953.6855822 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =44 , the width w =98 , and the height h =67 into the formula for surface area of a pyramid

A=($44 \cdot98+44$$\sqrt{(\frac{98}{2})^2+(67)^2}$$+98$$\sqrt{(\frac{44}{2})^2+(67)^2}$) ft

Simplify each term.

Multiply 44 ft by 98 ft

A = $4312.0 + 44$$\sqrt{(\frac{98}{2})^2+(67)^2}$$+98$$\sqrt{(\frac{44}{2})^2+(67)^2}$

Square root of $\sqrt{(\frac{98}{2})^2+(67)^2}$ is 83.0060239

Put The values in Area Formula:

A= $4312.0 + 44 \cdot 83.0060239 + 98$$\sqrt{(\frac{44}{2})^2 + (67)^2}$

Square Root of $\sqrt{(\frac{44}{2})^2+(67)^2}$ is 70.5195008

Put The values in Area Formula:

A= 4312.0 + 44 x 83.0060239 + 98 x 70.5195008

Multiply 44 and 83.0060239

A= 4312.0 + 3652.2650506 + 98 x 70.5195008

Multiply 98 and 70.5195008

A= 4312.0 + 3652.2650506 + 6910.9110832

Add 4312.0 and 3652.2650506

A=7964.2650506 + 6910.9110832

A= 14875.1761338 ft2

∴ The Surface Area of Pyramid length 44 ft , width 98 ft and height 67 ft is 14875.1761338 ft2