Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 42 yards by width 29 yards by height 54 yards is 5246.5899924 yards2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 42 yards by width 29 yards by height 54 yards is 5246.5899924 yards2.


    Surface Area of a Pyramid 42 yd by 29 yd by 54 yd in other units

Value unit
4.7974819 km2
2.9810245 mi2
4797.4818891 m2
15739.7699772 ft2
188877.2397264 in2
5246.5899924 yd2
479748.1889051 cm2
4797481.8890506 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =42 , the width w =29 , and the height h =54 into the formula for surface area of a pyramid

A=($42 \cdot29+42$$\sqrt{(\frac{29}{2})^2+(54)^2}$$+29$$\sqrt{(\frac{42}{2})^2+(54)^2}$) yd

Simplify each term.

Multiply 42 yd by 29 yd

A = $1218.0 + 42$$\sqrt{(\frac{29}{2})^2+(54)^2}$$+29$$\sqrt{(\frac{42}{2})^2+(54)^2}$

Square root of $\sqrt{(\frac{29}{2})^2+(54)^2}$ is 55.9128787

Put The values in Area Formula:

A= $1218.0 + 42 \cdot 55.9128787 + 29$$\sqrt{(\frac{42}{2})^2 + (54)^2}$

Square Root of $\sqrt{(\frac{42}{2})^2+(54)^2}$ is 57.9396237

Put The values in Area Formula:

A= 1218.0 + 42 x 55.9128787 + 29 x 57.9396237

Multiply 42 and 55.9128787

A= 1218.0 + 2348.3409037 + 29 x 57.9396237

Multiply 29 and 57.9396237

A= 1218.0 + 2348.3409037 + 1680.2490887

Add 1218.0 and 2348.3409037

A=3566.3409037 + 1680.2490887

A= 5246.5899924 yd2

∴ The Surface Area of Pyramid length 42 yd , width 29 yd and height 54 yd is 5246.5899924 yd2