Surface area of a Pyramid 42 yards by 29 yards by 54 yards Calculator
The Surface Area of Pyramid 42 yards by width 29 yards by height 54 yards is 5246.5899924 yards2.
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 42 yards by width 29 yards by height 54 yards is 5246.5899924 yards2.
Surface Area of a Pyramid 42 yd by 29 yd by 54 yd in other units
Value | unit |
---|---|
4.7974819 | km2 |
2.9810245 | mi2 |
4797.4818891 | m2 |
15739.7699772 | ft2 |
188877.2397264 | in2 |
5246.5899924 | yd2 |
479748.1889051 | cm2 |
4797481.8890506 | mm2 |
Steps:
The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$
Substitute the values of the length l =42 , the width w =29 , and the height h =54 into the formula for surface area of a pyramid
A=($42 \cdot29+42$$\sqrt{(\frac{29}{2})^2+(54)^2}$$+29$$\sqrt{(\frac{42}{2})^2+(54)^2}$) yd
Simplify each term.
Multiply 42 yd by 29 yd
A = $1218.0 + 42$$\sqrt{(\frac{29}{2})^2+(54)^2}$$+29$$\sqrt{(\frac{42}{2})^2+(54)^2}$
Square root of $\sqrt{(\frac{29}{2})^2+(54)^2}$ is 55.9128787
Put The values in Area Formula:
A= $1218.0 + 42 \cdot 55.9128787 + 29$$\sqrt{(\frac{42}{2})^2 + (54)^2}$
Square Root of $\sqrt{(\frac{42}{2})^2+(54)^2}$ is 57.9396237
Put The values in Area Formula:
A= 1218.0 + 42 x 55.9128787 + 29 x 57.9396237
Multiply 42 and 55.9128787
A= 1218.0 + 2348.3409037 + 29 x 57.9396237
Multiply 29 and 57.9396237
A= 1218.0 + 2348.3409037 + 1680.2490887
Add 1218.0 and 2348.3409037
A=3566.3409037 + 1680.2490887
A= 5246.5899924 yd2
∴ The Surface Area of Pyramid length 42 yd , width 29 yd and height 54 yd is 5246.5899924 yd2