Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 40 foot by width 98 foot by height 70 foot is 14472.3432639 foot2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 40 foot by width 98 foot by height 70 foot is 14472.3432639 foot2.


    Surface Area of a Pyramid 40 ft by 98 ft by 70 ft in other units

Value unit
4.4111702 km2
2.7409809 mi2
4411.1702268 m2
14472.3432639 ft2
173668.1191668 in2
4824.1144213 yd2
441117.0226837 cm2
4411170.2268367 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =40 , the width w =98 , and the height h =70 into the formula for surface area of a pyramid

A=($40 \cdot98+40$$\sqrt{(\frac{98}{2})^2+(70)^2}$$+98$$\sqrt{(\frac{40}{2})^2+(70)^2}$) ft

Simplify each term.

Multiply 40 ft by 98 ft

A = $3920.0 + 40$$\sqrt{(\frac{98}{2})^2+(70)^2}$$+98$$\sqrt{(\frac{40}{2})^2+(70)^2}$

Square root of $\sqrt{(\frac{98}{2})^2+(70)^2}$ is 85.4458893

Put The values in Area Formula:

A= $3920.0 + 40 \cdot 85.4458893 + 98$$\sqrt{(\frac{40}{2})^2 + (70)^2}$

Square Root of $\sqrt{(\frac{40}{2})^2+(70)^2}$ is 72.8010989

Put The values in Area Formula:

A= 3920.0 + 40 x 85.4458893 + 98 x 72.8010989

Multiply 40 and 85.4458893

A= 3920.0 + 3417.8355724 + 98 x 72.8010989

Multiply 98 and 72.8010989

A= 3920.0 + 3417.8355724 + 7134.5076915

Add 3920.0 and 3417.8355724

A=7337.8355724 + 7134.5076915

A= 14472.3432639 ft2

∴ The Surface Area of Pyramid length 40 ft , width 98 ft and height 70 ft is 14472.3432639 ft2