Surface area of a Pyramid 39 inches by 23 meters by 19 foot Calculator
The Surface Area of Pyramid 39 inches by width 23 meters by height 19 foot is 261560.5335612 inches2 or 1821.4959056 foot2 or 169.2225016 meters2
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 39 inches by width 23 meters by height 19 foot is 261560.5335612 inches2 or 1821.4959056 foot2 or 169.2225016 meters2
Surface Area of a Pyramid 39 in by 23 m by 19 ft in other units
| Value | unit |
|---|---|
| 6.6436376 | km2 |
| 4.1281752 | mi2 |
| 6643.6375525 | m2 |
| 21796.7111301 | ft2 |
| 261560.5335612 | in2 |
| 7265.5703767 | yd2 |
| 664363.7552454 | cm2 |
| 6643637.5524545 | mm2 |
Steps:
The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$
Substitute the values of the length l = 39 in, the width w = 23 m and the height h = 19 ft into the formula for surface area of a pyramid
Unit Conversion of 19 ft = 228.0 in
19 Foot is 228.0 inches
To convert Foot to Inches
we know that, 1 Foot = 12 inches
To convert Foot to inches, multiply the foot value by 12.
Result in Foot: 19 ft × 12 × in/ft
Cancel The Comman factor of ft
Result in Inches: (19 x 12 in)
Multiply 19 into 12
Result in Inches: 228.0 inches
∴ 19 Foot = 228.0 inches
Unit Conversion of 23 m = 905.51 in
23 meter is 905.51 inches
To convert Meters to Inches
we know that, 1 Meter = 39.37 Inch
To convert meter to Inch,multiply the meter value by 39.37.
Result in Inches: 23 m × 39.37 × in/m
Cancel The Comman factor of m
Result in Inches: (23 * 39.37 in)
Multiply 905.51 into 39.37
∴ 23 meter = 905.51 inches
A=($39 \cdot905.51+39$$\sqrt{(\frac{905.51}{2})^2+(228.0)^2}$$+905.51$$\sqrt{(\frac{39}{2})^2+(228.0)^2}$) in
Simplify each term.
Multiply 39 in by 905.51 in
A = $35314.89+39$$\sqrt{(\frac{905.51}{2})^2+(228.0)^2}$$+905.51$$\sqrt{(\frac{39}{2})^2+(228.0)^2}$
Square root of $\sqrt{(\frac{905.51}{2})^2+(228.0)^2}$ is 506.9231599
Put The values in Area Formula:
A= $35314.89+ 39 \cdot 506.9231599+905.51$$\sqrt{(\frac{39}{2})^2+(228.0)^2}$
Square Root of $\sqrt{(\frac{39}{2})^2+(228.0)^2}$ is 228.0213806
Put The values in Area Formula:
A= 35314.89 + (39 x 506.9231599) + (905.51 x 228.0213806)
Multiply 39 and 506.9231599
A= 35314.89 + 19770.0032354 + (905.51 x 228.0213806)
Multiply 905.51 and 228.0213806
A= 35314.89 + 19770.0032354 + 206475.6403258
Add 35314.89 and 19770.0032354
A= 55084.8932354 + 206475.6403258
A= 261560.5335612 in2
∴ The Surface Area of Pyramid length 39 in , width 23 m and height 19 ft is 261560.5335612 in2
or
Unit Conversion of 23 m = 75.45932 ft
23 Meters is 75.45932 foot
To convert Meters to Foot
we know that, 1 Meter = 3.28084 Foot
To convert Meter to Foot, multiply the meter value by 3.28084.
Result in Foot: 23 m × 3.28084 × ft/m
Cancel The Comman factor of m
Result in Foot: (23 x 3.28084 ft)
Multiply 23 into 3.28084
Result in Foot: 75.45932 foot
∴ 23 Meters = 75.45932 foot
Unit Conversion of 39 in = 3.25 ft
39 Inches is 3.25 feet
To convert Inches to Feet
we know that, 1 Inches = 0.0833333 Feet or
1 Foot = 1/12 foot
To convert Inches to Feet, divide the inche value by 12.
Result in Foot: 39 × in/12 × ft/in
Cancel The Comman factor of in
Result in Feet: $39\above 1pt12$
Divide the 39 by 12
Result in Feet: 3.25 feet
∴ 39 Inches = 3.25 feet
A=($3.25 \cdot75.45932+3.25$$\sqrt{(\frac{75.45932}{2})^2+(19)^2}$$+75.45932$$\sqrt{(\frac{3.25}{2})^2+(19)^2}$) ft
Simplify each term.
Multiply 3.25 ft by 75.45932 ft
A = $245.24279+3.25$$\sqrt{(\frac{75.45932}{2})^2+(19)^2}$$+75.45932$$\sqrt{(\frac{3.25}{2})^2+(19)^2}$
Square root of $\sqrt{(\frac{75.45932}{2})^2+(19)^2}$ is 42.2436651
Put The values in Area Formula:
A= $245.24279+ 3.25 \cdot 42.2436651+75.45932$$\sqrt{(\frac{3.25}{2})^2+(19)^2}$
Square Root of $\sqrt{(\frac{3.25}{2})^2+(19)^2}$ is 19.0693635
Put The values in Area Formula:
A= 245.24279 + (3.25 x 42.2436651) + (75.45932 x 19.0693635)
Multiply 3.25 and 42.2436651
A= 245.24279 + 137.2919117 + (75.45932 x 19.0693635)
Multiply 75.45932 and 19.0693635
A= 245.24279 + 137.2919117 + 1438.9612039
Add 245.24279 and 137.2919117
A= 382.5347017 + 1438.9612039
A=$1821.4959056$ ft2
∴ The Surface Area of Pyramid length 39 in , width 23 m and height 19 ft is 1821.4959056 ft2
or
Unit Conversion of 39 in = 0.9906 m
39 inches is 0.9906 meters
To convert inches to meter
we know that, 1 inch = 0.0254 meters
To convert inches to meter,multiply the inches value by 0.0254.
Result in Inches: 39 in x 0.0254 × m/in
Cancel The Comman factor of m
Result in Meters: (39 x 0.0254 m)
Multiply 39 into 0.0254
Result in meters: 0.9906 meters
∴ 39 inches = 0.9906 meters
Unit Conversion of 19 ft = 5.7912 m
19 Foot is 5.7912 meters
To convert Feet to Meter
we know that, 1 Foot = 0.3048 Meter
To convert Foot to meters, multiply the feet value by 0.3048.
Result in Meter: 19 ft × 0.3048 × m/ft
Cancel The Comman factor of ft
Result in Meters: (19 x 0.3048 m)
Multiply 19 into 0.3048
Result in Meters: 5.7912 meters
∴ 19 Foot = 5.7912 meters
A=($0.9906 \cdot23+0.9906$$\sqrt{(\frac{23}{2})^2+(5.7912)^2}$$+23$$\sqrt{(\frac{0.9906}{2})^2+(5.7912)^2}$) m
Simplify each term.
Multiply 0.9906 m by 23 m
A = $22.7838+0.9906$$\sqrt{(\frac{23}{2})^2+(5.7912)^2}$$+23$$\sqrt{(\frac{0.9906}{2})^2+(5.7912)^2}$
Square root of $\sqrt{(\frac{23}{2})^2+(19)^2}$ is 12.8758688
Put The values in Area Formula:
A= $22.7838+ 0.9906 \cdot 12.8758688+23$$\sqrt{(\frac{0.9906}{2})^2+(5.7912)^2}$
Square Root of $\sqrt{(\frac{0.9906}{2})^2+(5.7912)^2}$ is 5.812342
Put The values in Area Formula:
A = 22.7838 + (0.9906 x 12.8758688) + (23 x 5.812342)
Multiply 0.9906 and 12.8758688
A = 22.7838 + 12.7548356 +(23 x 5.812342)
Multiply 23 and 5.812342
A= 22.7838 + 12.7548356 + 133.683866
Add 22.7838 and 12.7548356
A = 35.5386356 + 133.683866
A= 169.2225016 m2
∴ The Surface Area of Pyramid length 39 in , width 23 m and height 19 ft is 169.2225016 m2