Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base(base 1)

Enter the Base (base 2)

Enter the height


The Surface Area of Pyramid 35 yards by width 23 yards by height 56 yards is 4155.3272558 yards2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 35 yards by width 23 yards by height 56 yards is 4155.3272558 yards2.


    Surface Area of a Pyramid 35 yd by 23 yd by 56 yd in other units

Value unit
3.7996312 km2
2.3609873 mi2
3799.6312427 m2
12465.9817674 ft2
149591.7812088 in2
4155.3272558 yd2
379963.1242704 cm2
3799631.2427035 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =35 , the width w =23 , and the height h =56 into the formula for surface area of a pyramid

A=($35 \cdot23+35$$\sqrt{(\frac{23}{2})^2+(56)^2}$$+23$$\sqrt{(\frac{35}{2})^2+(56)^2}$) yd

Simplify each term.

Multiply 35 yd by 23 yd

A = $805.0 + 35$$\sqrt{(\frac{23}{2})^2+(56)^2}$$+23$$\sqrt{(\frac{35}{2})^2+(56)^2}$

Square root of $\sqrt{(\frac{23}{2})^2+(56)^2}$ is 57.1686103

Put The values in Area Formula:

A= $805.0 + 35 \cdot 57.1686103 + 23$$\sqrt{(\frac{35}{2})^2 + (56)^2}$

Square Root of $\sqrt{(\frac{35}{2})^2+(56)^2}$ is 58.6706911

Put The values in Area Formula:

A= 805.0 + 35 x 57.1686103 + 23 x 58.6706911

Multiply 35 and 57.1686103

A= 805.0 + 2000.9013594 + 23 x 58.6706911

Multiply 23 and 58.6706911

A= 805.0 + 2000.9013594 + 1349.4258964

Add 805.0 and 2000.9013594

A=2805.9013594 + 1349.4258964

A= 4155.3272558 yd2

∴ The Surface Area of Pyramid length 35 yd , width 23 yd and height 56 yd is 4155.3272558 yd2