Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 25 meters by width 94 meters by height 87 meters is 13084.0739803 meters2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 25 meters by width 94 meters by height 87 meters is 13084.0739803 meters2.


    Surface Area of a Pyramid 25 m by 94 m by 87 m in other units

Value unit
13.084074 km2
8.1300869 mi2
13084.0739803 m2
42926.7519039 ft2
515121.0228465 in2
14308.9173013 yd2
1308407.39803 cm2
13084073.9803 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =25 , the width w =94 , and the height h =87 into the formula for surface area of a pyramid

A=($25 \cdot94+25$$\sqrt{(\frac{94}{2})^2+(87)^2}$$+94$$\sqrt{(\frac{25}{2})^2+(87)^2}$) m

Simplify each term.

Multiply 25 m by 94 m

A = $2350.0 + 25$$\sqrt{(\frac{94}{2})^2+(87)^2}$$+94$$\sqrt{(\frac{25}{2})^2+(87)^2}$

Square root of $\sqrt{(\frac{94}{2})^2+(87)^2}$ is 98.8837702

Put The values in Area Formula:

A= $2350.0 + 25 \cdot 98.8837702 + 94$$\sqrt{(\frac{25}{2})^2 + (87)^2}$

Square Root of $\sqrt{(\frac{25}{2})^2+(87)^2}$ is 87.8934013

Put The values in Area Formula:

A= 2350.0 + 25 x 98.8837702 + 94 x 87.8934013

Multiply 25 and 98.8837702

A= 2350.0 + 2472.0942539 + 94 x 87.8934013

Multiply 94 and 87.8934013

A= 2350.0 + 2472.0942539 + 8261.9797264

Add 2350.0 and 2472.0942539

A=4822.0942539 + 8261.9797264

A= 13084.0739803 m2

∴ The Surface Area of Pyramid length 25 m , width 94 m and height 87 m is 13084.0739803 m2