Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 17 meters by width 84 meters by height 77 meters is 9426.3554847 meters2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 17 meters by width 84 meters by height 77 meters is 9426.3554847 meters2.


    Surface Area of a Pyramid 17 m by 84 m by 77 m in other units

Value unit
9.4263555 km2
5.8572803 mi2
9426.3554847 m2
30926.3631388 ft2
371116.3576654 in2
10308.7877129 yd2
942635.54847 cm2
9426355.4847 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =17 , the width w =84 , and the height h =77 into the formula for surface area of a pyramid

A=($17 \cdot84+17$$\sqrt{(\frac{84}{2})^2+(77)^2}$$+84$$\sqrt{(\frac{17}{2})^2+(77)^2}$) m

Simplify each term.

Multiply 17 m by 84 m

A = $1428.0 + 17$$\sqrt{(\frac{84}{2})^2+(77)^2}$$+84$$\sqrt{(\frac{17}{2})^2+(77)^2}$

Square root of $\sqrt{(\frac{84}{2})^2+(77)^2}$ is 87.7097486

Put The values in Area Formula:

A= $1428.0 + 17 \cdot 87.7097486 + 84$$\sqrt{(\frac{17}{2})^2 + (77)^2}$

Square Root of $\sqrt{(\frac{17}{2})^2+(77)^2}$ is 77.4677352

Put The values in Area Formula:

A= 1428.0 + 17 x 87.7097486 + 84 x 77.4677352

Multiply 17 and 87.7097486

A= 1428.0 + 1491.0657263 + 84 x 77.4677352

Multiply 84 and 77.4677352

A= 1428.0 + 1491.0657263 + 6507.2897584

Add 1428.0 and 1491.0657263

A=2919.0657263 + 6507.2897584

A= 9426.3554847 m2

∴ The Surface Area of Pyramid length 17 m , width 84 m and height 77 m is 9426.3554847 m2