Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 15 inches by width 39 inches by height 37 inches is 2684.7073934 inches2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 15 inches by width 39 inches by height 37 inches is 2684.7073934 inches2.


    Surface Area of a Pyramid 15 in by 39 in by 37 in in other units

Value unit
0.0681916 km2
0.0423724 mi2
68.1915678 m2
223.7256161 ft2
2684.7073934 in2
74.5752054 yd2
6819.1567792 cm2
68191.5677924 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =15 , the width w =39 , and the height h =37 into the formula for surface area of a pyramid

A=($15 \cdot39+15$$\sqrt{(\frac{39}{2})^2+(37)^2}$$+39$$\sqrt{(\frac{15}{2})^2+(37)^2}$) in

Simplify each term.

Multiply 15 in by 39 in

A = $585.0 + 15$$\sqrt{(\frac{39}{2})^2+(37)^2}$$+39$$\sqrt{(\frac{15}{2})^2+(37)^2}$

Square root of $\sqrt{(\frac{39}{2})^2+(37)^2}$ is 41.8240362

Put The values in Area Formula:

A= $585.0 + 15 \cdot 41.8240362 + 39$$\sqrt{(\frac{15}{2})^2 + (37)^2}$

Square Root of $\sqrt{(\frac{15}{2})^2+(37)^2}$ is 37.7524834

Put The values in Area Formula:

A= 585.0 + 15 x 41.8240362 + 39 x 37.7524834

Multiply 15 and 41.8240362

A= 585.0 + 627.3605423 + 39 x 37.7524834

Multiply 39 and 37.7524834

A= 585.0 + 627.3605423 + 1472.3468511

Add 585.0 and 627.3605423

A=1212.3605423 + 1472.3468511

A= 2684.7073934 in2

∴ The Surface Area of Pyramid length 15 in , width 39 in and height 37 in is 2684.7073934 in2