Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 11 foot by width 64 foot by height 17 foot is 2246.1131372 foot2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 11 foot by width 64 foot by height 17 foot is 2246.1131372 foot2.


    Surface Area of a Pyramid 11 ft by 64 ft by 17 ft in other units

Value unit
0.6846153 km2
0.4254013 mi2
684.6152842 m2
2246.1131372 ft2
26953.3576464 in2
748.7043791 yd2
68461.5284219 cm2
684615.2842186 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =11 , the width w =64 , and the height h =17 into the formula for surface area of a pyramid

A=($11 \cdot64+11$$\sqrt{(\frac{64}{2})^2+(17)^2}$$+64$$\sqrt{(\frac{11}{2})^2+(17)^2}$) ft

Simplify each term.

Multiply 11 ft by 64 ft

A = $704.0 + 11$$\sqrt{(\frac{64}{2})^2+(17)^2}$$+64$$\sqrt{(\frac{11}{2})^2+(17)^2}$

Square root of $\sqrt{(\frac{64}{2})^2+(17)^2}$ is 36.2353419

Put The values in Area Formula:

A= $704.0 + 11 \cdot 36.2353419 + 64$$\sqrt{(\frac{11}{2})^2 + (17)^2}$

Square Root of $\sqrt{(\frac{11}{2})^2+(17)^2}$ is 17.8675684

Put The values in Area Formula:

A= 704.0 + 11 x 36.2353419 + 64 x 17.8675684

Multiply 11 and 36.2353419

A= 704.0 + 398.5887605 + 64 x 17.8675684

Multiply 64 and 17.8675684

A= 704.0 + 398.5887605 + 1143.5243767

Add 704.0 and 398.5887605

A=1102.5887605 + 1143.5243767

A= 2246.1131372 ft2

∴ The Surface Area of Pyramid length 11 ft , width 64 ft and height 17 ft is 2246.1131372 ft2