Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 10 foot by width 93 foot by height 27 foot is 4021.3960704 foot2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 10 foot by width 93 foot by height 27 foot is 4021.3960704 foot2.


    Surface Area of a Pyramid 10 ft by 93 ft by 27 ft in other units

Value unit
1.2257215 km2
0.7616299 mi2
1225.7215223 m2
4021.3960704 ft2
48256.7528448 in2
1340.4653568 yd2
122572.1522258 cm2
1225721.5222579 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =10 , the width w =93 , and the height h =27 into the formula for surface area of a pyramid

A=($10 \cdot93+10$$\sqrt{(\frac{93}{2})^2+(27)^2}$$+93$$\sqrt{(\frac{10}{2})^2+(27)^2}$) ft

Simplify each term.

Multiply 10 ft by 93 ft

A = $930.0 + 10$$\sqrt{(\frac{93}{2})^2+(27)^2}$$+93$$\sqrt{(\frac{10}{2})^2+(27)^2}$

Square root of $\sqrt{(\frac{93}{2})^2+(27)^2}$ is 53.770345

Put The values in Area Formula:

A= $930.0 + 10 \cdot 53.770345 + 93$$\sqrt{(\frac{10}{2})^2 + (27)^2}$

Square Root of $\sqrt{(\frac{10}{2})^2+(27)^2}$ is 27.4590604

Put The values in Area Formula:

A= 930.0 + 10 x 53.770345 + 93 x 27.4590604

Multiply 10 and 53.770345

A= 930.0 + 537.7034499 + 93 x 27.4590604

Multiply 93 and 27.4590604

A= 930.0 + 537.7034499 + 2553.6926205

Add 930.0 and 537.7034499

A=1467.7034499 + 2553.6926205

A= 4021.3960704 ft2

∴ The Surface Area of Pyramid length 10 ft , width 93 ft and height 27 ft is 4021.3960704 ft2