Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 10 foot by width 93 foot by height 26 foot is 3925.0579145 foot2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 10 foot by width 93 foot by height 26 foot is 3925.0579145 foot2.


    Surface Area of a Pyramid 10 ft by 93 ft by 26 ft in other units

Value unit
1.1963577 km2
0.743384 mi2
1196.3576523 m2
3925.0579145 ft2
47100.694974 in2
1308.3526382 yd2
119635.765234 cm2
1196357.6523396 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =10 , the width w =93 , and the height h =26 into the formula for surface area of a pyramid

A=($10 \cdot93+10$$\sqrt{(\frac{93}{2})^2+(26)^2}$$+93$$\sqrt{(\frac{10}{2})^2+(26)^2}$) ft

Simplify each term.

Multiply 10 ft by 93 ft

A = $930.0 + 10$$\sqrt{(\frac{93}{2})^2+(26)^2}$$+93$$\sqrt{(\frac{10}{2})^2+(26)^2}$

Square root of $\sqrt{(\frac{93}{2})^2+(26)^2}$ is 53.2752288

Put The values in Area Formula:

A= $930.0 + 10 \cdot 53.2752288 + 93$$\sqrt{(\frac{10}{2})^2 + (26)^2}$

Square Root of $\sqrt{(\frac{10}{2})^2+(26)^2}$ is 26.4764046

Put The values in Area Formula:

A= 930.0 + 10 x 53.2752288 + 93 x 26.4764046

Multiply 10 and 53.2752288

A= 930.0 + 532.7522877 + 93 x 26.4764046

Multiply 93 and 26.4764046

A= 930.0 + 532.7522877 + 2462.3056268

Add 930.0 and 532.7522877

A=1462.7522877 + 2462.3056268

A= 3925.0579145 ft2

∴ The Surface Area of Pyramid length 10 ft , width 93 ft and height 26 ft is 3925.0579145 ft2