Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Surface area of a Box length 52 inches by width 90 inches by height 58 inches is 25832.0 inches2.

The Surface Area of a Box is equal to the sum of the areas of each side of the box. If the box has a length 52 inches by width 90 inches by height 58 inches is 25832.0 inches2.


    Surface Area of a Box 52 in by 90 in by 58 in in other units

Value unit
0.6561328 km2
0.407703 mi2
656.1328 m2
2152.6666667 ft2
25832.0 in2
717.5555556 yd2
65613.28 cm2
656132.8 mm2

Steps:

The Surface Area of a Box 2 * (length * width) + 2 * (length * height) + 2 * (width * height)

Substitute the values of the length l = 52 in , the width w = 90 in , and the height h = 58 in into the formula

2 * (52 in * 90 in) + 2 * (52 in* 58 in) + 2 * (90 in* 58 in)

Simplify each term

2 * 4680.0 in2 + 2 * 3016.0 in2 + 2 * 5220.0 in2

Multiply each term with 2

9360.0 in2 + 6032.0 in2 + 10440.0 in2

Simplify by adding three(3) term or numbers

Surface area = 25832.0 in2

∴ Surface area of a Box length 52 in , width 90 in and height 58 in is 25832.0 in2