Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Surface area of a Box length 50 inches by width 78 inches by height 22 inches is 13432.0 inches2.

The Surface Area of a Box is equal to the sum of the areas of each side of the box. If the box has a length 50 inches by width 78 inches by height 22 inches is 13432.0 inches2.


    Surface Area of a Box 50 in by 78 in by 22 in in other units

Value unit
0.3411728 km2
0.2119955 mi2
341.1728 m2
1119.3333333 ft2
13432.0 in2
373.1111111 yd2
34117.28 cm2
341172.8 mm2

Steps:

The Surface Area of a Box 2 * (length * width) + 2 * (length * height) + 2 * (width * height)

Substitute the values of the length l = 50 in , the width w = 78 in , and the height h = 22 in into the formula

2 * (50 in * 78 in) + 2 * (50 in* 22 in) + 2 * (78 in* 22 in)

Simplify each term

2 * 3900.0 in2 + 2 * 1100.0 in2 + 2 * 1716.0 in2

Multiply each term with 2

7800.0 in2 + 2200.0 in2 + 3432.0 in2

Simplify by adding three(3) term or numbers

Surface area = 13432.0 in2

∴ Surface area of a Box length 50 in , width 78 in and height 22 in is 13432.0 in2