Area of a Trapezoid 53 inches by 17 inches by 56 inches Calculator
Area of a Trapezoid 53 inches,17 and 56 is 1960.0 inches2
Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 53 inches,base2 17 and 56 is 1960.0 inches2
Area of Trapezoid 53 in by 17 in by 56 in in other units
| Value | unit |
|---|---|
| 0.049784 | km2 |
| 0.0309344 | mi2 |
| 49.784 | m2 |
| 163.3333333 | ft2 |
| 1960.0 | in2 |
| 54.4444444 | yd2 |
| 4978.4 | cm2 |
| 49784.0 | mm2 |
Steps:
Given that base1 = 53 in and base2 = 17 in and height =56 in
Substitute the values of the bases(b1 = 53 in and b2 = 17 in) and height h = 56 56 into the formula for the area of a trapezoid.
Area = $1\above 1pt2$ * height * (base1 +base2)
Put the value of base and height value in Area Formula.
Area = $1\above 1pt2$ * (56 in) * (53 + 17) in
Add the bases value b1 = 53 in and b2 = 17 in
Area = $1\above 1pt2$ * 56 in * (70.0 in)
Multiply 56 in and 70.0 in
Area = $1\above 1pt2$ * 3920.0 in2
Divide 3920.0 in by 2
Area = 1960.0 in2
∴ Area of a Trapezoid 53 in by 17 in by 56 in is 1960.0 in2