Area of a Trapezoid 41 inches by 42 inches by 16 inches Calculator
Area of a Trapezoid 41 inches,42 and 16 is 664.0 inches2
Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 41 inches,base2 42 and 16 is 664.0 inches2
Area of Trapezoid 41 in by 42 in by 16 in in other units
| Value | unit |
|---|---|
| 0.0168656 | km2 |
| 0.0104798 | mi2 |
| 16.8656 | m2 |
| 55.3333333 | ft2 |
| 664.0 | in2 |
| 18.4444444 | yd2 |
| 1686.56 | cm2 |
| 16865.6 | mm2 |
Steps:
Given that base1 = 41 in and base2 = 42 in and height =16 in
Substitute the values of the bases(b1 = 41 in and b2 = 42 in) and height h = 16 16 into the formula for the area of a trapezoid.
Area = $1\above 1pt2$ * height * (base1 +base2)
Put the value of base and height value in Area Formula.
Area = $1\above 1pt2$ * (16 in) * (41 + 42) in
Add the bases value b1 = 41 in and b2 = 42 in
Area = $1\above 1pt2$ * 16 in * (83.0 in)
Multiply 16 in and 83.0 in
Area = $1\above 1pt2$ * 1328.0 in2
Divide 1328.0 in by 2
Area = 664.0 in2
∴ Area of a Trapezoid 41 in by 42 in by 16 in is 664.0 in2