Area of a Trapezoid 27 foot by 33 foot by 65 foot Calculator
Area of a Trapezoid 27 foot,33 and 65 is 1950.0 foot2
Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 27 foot,base2 33 and 65 is 1950.0 foot2
Area of Trapezoid 27 ft by 33 ft by 65 ft in other units
Value | unit |
---|---|
0.59436 | km2 |
0.3693191 | mi2 |
594.36 | m2 |
1950.0 | ft2 |
23400.0 | in2 |
650.0 | yd2 |
59436.0 | cm2 |
594360.0 | mm2 |
Steps:
Given that base1 = 27 ft and base2 = 33 ft and height =65 ft
Substitute the values of the bases(b1 = 27 ft and b2 = 33 ft) and height h = 65 65 into the formula for the area of a trapezoid.
Area = $1\above 1pt2$ * height * (base1 +base2)
Put the value of base and height value in Area Formula.
Area = $1\above 1pt2$ * (65 ft) * (27 + 33) ft
Add the bases value b1 = 27 ft and b2 = 33 ft
Area = $1\above 1pt2$ * 65 ft * (60.0 ft)
Multiply 65 ft and 60.0 ft
Area = $1\above 1pt2$ * 3900.0 ft2
Divide 3900.0 ft by 2
Area = 1950.0 ft2
∴ Area of a Trapezoid 27 ft by 33 ft by 65 ft is 1950.0 ft2