Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base (base 1)

Enter the Base (base 2)

Enter the height


Area of a Trapezoid 27 foot,33 and 65 is 1950.0 foot2

Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 27 foot,base2 33 and 65 is 1950.0 foot2


    Area of Trapezoid 27 ft by 33 ft by 65 ft in other units

Value unit
0.59436 km2
0.3693191 mi2
594.36 m2
1950.0 ft2
23400.0 in2
650.0 yd2
59436.0 cm2
594360.0 mm2

Steps:

Given that base1 = 27 ft and base2 = 33 ft and height =65 ft

Substitute the values of the bases(b1 = 27 ft and b2 = 33 ft) and height h = 65 65 into the formula for the area of a trapezoid.

Area = $1\above 1pt2$ * height * (base1 +base2)

Put the value of base and height value in Area Formula.

Area = $1\above 1pt2$ * (65 ft) * (27 + 33) ft

Add the bases value b1 = 27 ft and b2 = 33 ft

Area = $1\above 1pt2$ * 65 ft * (60.0 ft)

Multiply 65 ft and 60.0 ft

Area = $1\above 1pt2$ * 3900.0 ft2

Divide 3900.0 ft by 2

Area = 1950.0 ft2

∴ Area of a Trapezoid 27 ft by 33 ft by 65 ft is 1950.0 ft2