Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base (base 1)

Enter the Base (base 2)

Enter the height


Area of a Trapezoid 23 centimeters,12 and 6 is 105.0 centimeters2

Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 23 centimeters,base2 12 and 6 is 105.0 centimeters2


    Area of Trapezoid 23 cm by 12 cm by 6 cm in other units

Value unit
0.00105 km2
0.0006524 mi2
1.05 m2
3.4448819 ft2
41.3385827 in2
1.148294 yd2
105.0 cm2
1050.0 mm2

Steps:

Given that base1 = 23 cm and base2 = 12 cm and height =6 cm

Substitute the values of the bases(b1 = 23 cm and b2 = 12 cm) and height h = 6 6 into the formula for the area of a trapezoid.

Area = $1\above 1pt2$ * height * (base1 +base2)

Put the value of base and height value in Area Formula.

Area = $1\above 1pt2$ * (6 cm) * (23 + 12) cm

Add the bases value b1 = 23 cm and b2 = 12 cm

Area = $1\above 1pt2$ * 6 cm * (35.0 cm)

Multiply 6 cm and 35.0 cm

Area = $1\above 1pt2$ * 210.0 cm2

Divide 210.0 cm by 2

Area = 105.0 cm2

∴ Area of a Trapezoid 23 cm by 12 cm by 6 cm is 105.0 cm2