Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base (base 1)

Enter the Base (base 2)

Enter the height


Area of a Trapezoid 17 foot,58 and 77 is 2887.5 foot2

Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 17 foot,base2 58 and 77 is 2887.5 foot2


    Area of Trapezoid 17 ft by 58 ft by 77 ft in other units

Value unit
0.88011 km2
0.5468764 mi2
880.11 m2
2887.5 ft2
34650.0 in2
962.5 yd2
88011.0 cm2
880110.0 mm2

Steps:

Given that base1 = 17 ft and base2 = 58 ft and height =77 ft

Substitute the values of the bases(b1 = 17 ft and b2 = 58 ft) and height h = 77 77 into the formula for the area of a trapezoid.

Area = $1\above 1pt2$ * height * (base1 +base2)

Put the value of base and height value in Area Formula.

Area = $1\above 1pt2$ * (77 ft) * (17 + 58) ft

Add the bases value b1 = 17 ft and b2 = 58 ft

Area = $1\above 1pt2$ * 77 ft * (75.0 ft)

Multiply 77 ft and 75.0 ft

Area = $1\above 1pt2$ * 5775.0 ft2

Divide 5775.0 ft by 2

Area = 2887.5 ft2

∴ Area of a Trapezoid 17 ft by 58 ft by 77 ft is 2887.5 ft2