Area of a Trapezoid 17 foot by 58 foot by 77 foot Calculator
Area of a Trapezoid 17 foot,58 and 77 is 2887.5 foot2
Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 17 foot,base2 58 and 77 is 2887.5 foot2
Area of Trapezoid 17 ft by 58 ft by 77 ft in other units
Value | unit |
---|---|
0.88011 | km2 |
0.5468764 | mi2 |
880.11 | m2 |
2887.5 | ft2 |
34650.0 | in2 |
962.5 | yd2 |
88011.0 | cm2 |
880110.0 | mm2 |
Steps:
Given that base1 = 17 ft and base2 = 58 ft and height =77 ft
Substitute the values of the bases(b1 = 17 ft and b2 = 58 ft) and height h = 77 77 into the formula for the area of a trapezoid.
Area = $1\above 1pt2$ * height * (base1 +base2)
Put the value of base and height value in Area Formula.
Area = $1\above 1pt2$ * (77 ft) * (17 + 58) ft
Add the bases value b1 = 17 ft and b2 = 58 ft
Area = $1\above 1pt2$ * 77 ft * (75.0 ft)
Multiply 77 ft and 75.0 ft
Area = $1\above 1pt2$ * 5775.0 ft2
Divide 5775.0 ft by 2
Area = 2887.5 ft2
∴ Area of a Trapezoid 17 ft by 58 ft by 77 ft is 2887.5 ft2