Area of a Trapezoid 15 inches by 11 inches by 36 inches Calculator
Area of a Trapezoid 15 inches,11 and 36 is 468.0 inches2
Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 15 inches,base2 11 and 36 is 468.0 inches2
Area of Trapezoid 15 in by 11 in by 36 in in other units
| Value | unit |
|---|---|
| 0.0118872 | km2 |
| 0.0073864 | mi2 |
| 11.8872 | m2 |
| 39.0 | ft2 |
| 468.0 | in2 |
| 13.0 | yd2 |
| 1188.72 | cm2 |
| 11887.2 | mm2 |
Steps:
Given that base1 = 15 in and base2 = 11 in and height =36 in
Substitute the values of the bases(b1 = 15 in and b2 = 11 in) and height h = 36 36 into the formula for the area of a trapezoid.
Area = $1\above 1pt2$ * height * (base1 +base2)
Put the value of base and height value in Area Formula.
Area = $1\above 1pt2$ * (36 in) * (15 + 11) in
Add the bases value b1 = 15 in and b2 = 11 in
Area = $1\above 1pt2$ * 36 in * (26.0 in)
Multiply 36 in and 26.0 in
Area = $1\above 1pt2$ * 936.0 in2
Divide 936.0 in by 2
Area = 468.0 in2
∴ Area of a Trapezoid 15 in by 11 in by 36 in is 468.0 in2