Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : Jan 03, 2024


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Diagonal (e)
Diagonal (f)
Angle α


Area of an Irregular Quadrilateral diagonal (e) = 97 m, diagonal(f) = 62 m and degrees = 161 is 1957.9668809 m2

Area of an Irregular Quadrilateral diagonal (e) = 97 m, diagonal(f) = 62 m and degrees = 161 is 1957.9668809 m2


  Area of an Irregular Quadrilateral diagonal (e) = 97 m, diagonal(f) = 62 m and degrees = 161 in other units

Value unit
1.9579669 km²
1.2166272 mi²
1957.9668809
6423.775856 ft²
77085.3102717 in²
2141.2586187 yd²
195796.68809 cm²
1957966.8809 mm²

Steps:

Given that Irregular Quadrilateral diagonal (e) = 97 m, diagonal(f) = 62 m and radians = 161

We know that, Area = e * f * sin(α)

Put the values of e, f and α in above Area Formula

A = 97 * 62 * sin(1610 )

Simplify the above equation

A = 1957.9668809 m²

∴ Area of an Irregular Quadrilateral diagonal (e) = 97 m, diagonal(f) = 62 m and degrees = 161 is 1957.9668809 m²