Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : Jan 03, 2024


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Diagonal (e)
Diagonal (f)
Angle α


Area of an Irregular Quadrilateral diagonal (e) = 92 yd, diagonal(f) = 45 yd and degrees = 122 is 3510.9191181 yd2

Area of an Irregular Quadrilateral diagonal (e) = 92 yd, diagonal(f) = 45 yd and degrees = 122 is 3510.9191181 yd2


  Area of an Irregular Quadrilateral diagonal (e) = 92 yd, diagonal(f) = 45 yd and degrees = 122 in other units

Value unit
3.2103844 km²
1.9948454 mi²
3210.3844416
10532.7573543 ft²
126393.0882516 in²
3510.9191181 yd²
321038.4441591 cm²
3210384.4415906 mm²

Steps:

Given that Irregular Quadrilateral diagonal (e) = 92 yd, diagonal(f) = 45 yd and radians = 122

We know that, Area = e * f * sin(α)

Put the values of e, f and α in above Area Formula

A = 92 * 45 * sin(1220 )

Simplify the above equation

A = 3510.9191181 yd²

∴ Area of an Irregular Quadrilateral diagonal (e) = 92 yd, diagonal(f) = 45 yd and degrees = 122 is 3510.9191181 yd²