Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : Jan 03, 2024


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Diagonal (e)
Diagonal (f)
Angle α


Area of an Irregular Quadrilateral diagonal (e) = 87 yd, diagonal(f) = 68 yd and degrees = 138 is 3958.5766672 yd2

Area of an Irregular Quadrilateral diagonal (e) = 87 yd, diagonal(f) = 68 yd and degrees = 138 is 3958.5766672 yd2


  Area of an Irregular Quadrilateral diagonal (e) = 87 yd, diagonal(f) = 68 yd and degrees = 138 in other units

Value unit
3.6197225 km²
2.2491969 mi²
3619.7225045
11875.7300016 ft²
142508.7600192 in²
3958.5766672 yd²
361972.2504488 cm²
3619722.5044877 mm²

Steps:

Given that Irregular Quadrilateral diagonal (e) = 87 yd, diagonal(f) = 68 yd and radians = 138

We know that, Area = e * f * sin(α)

Put the values of e, f and α in above Area Formula

A = 87 * 68 * sin(1380 )

Simplify the above equation

A = 3958.5766672 yd²

∴ Area of an Irregular Quadrilateral diagonal (e) = 87 yd, diagonal(f) = 68 yd and degrees = 138 is 3958.5766672 yd²