Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : Jan 03, 2024


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Diagonal (e)
Diagonal (f)
Angle α


Area of an Irregular Quadrilateral diagonal (e) = 87 in, diagonal(f) = 30 in and degrees = 85 is 2600.068162 in2

Area of an Irregular Quadrilateral diagonal (e) = 87 in, diagonal(f) = 30 in and degrees = 85 is 2600.068162 in2


  Area of an Irregular Quadrilateral diagonal (e) = 87 in, diagonal(f) = 30 in and degrees = 85 in other units

Value unit
0.0660417 km²
0.0410365 mi²
66.0417313
216.6723468 ft²
2600.068162 in²
72.2241156 yd²
6604.1731315 cm²
66041.7313148 mm²

Steps:

Given that Irregular Quadrilateral diagonal (e) = 87 in, diagonal(f) = 30 in and radians = 85

We know that, Area = e * f * sin(α)

Put the values of e, f and α in above Area Formula

A = 87 * 30 * sin(850 )

Simplify the above equation

A = 2600.068162 in²

∴ Area of an Irregular Quadrilateral diagonal (e) = 87 in, diagonal(f) = 30 in and degrees = 85 is 2600.068162 in²