Area of an Irregular Quadrilateral Calculator
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Area of an Irregular Quadrilateral diagonal (e) = 7 in, diagonal(f) = 22 ft and diagonal = 118 is 1631.6871516 in2 or 11.3311601 ft2.
Area of an Irregular Quadrilateral diagonal (e) = 7 in, diagonal(f) = 22 ft and diagonal = 118 is 1631.6871516 in2 or 11.3311601 ft2.
Area of an Irregular Quadrilateral diagonal (e) = 7 in, diagonal(f) = 22 ft and diagonal = 118 in other units
| Value | unit |
|---|---|
| 0.0414449 | km² |
| 0.0257527 | mi² |
| 41.4448537 | m² |
| 135.9739293 | ft² |
| 1631.6871516 | in² |
| 45.3246431 | yd² |
| 4144.4853651 | cm² |
| 41444.8536506 | mm² |
Steps:
Given that Irregular Quadrilateral diagonal (e) = 7 in, diagonal(f) = 22 ft and radians = 118
We know that, Area = e * f * sin(α)
Put the values of e, f and α in above Area Formula
Unit Conversion of Width 22 ft = 264.0 in
22 Foot is 264.0 inches
To convert Foot to Inches
we know that, 1 Foot = 12 inches
To convert Foot to inches, multiply the foot value by 12.
Result in Foot: 22 ft × 12 × in/ft
Cancel The Comman factor of ft
Result in Inches: (22 x 12 in)
Multiply 22 into 12
Result in Inches: 264.0 inches
∴ 22 Foot = 264.0 inches
A = 7 * 264.0 * sin(1180)
Simplify the above equation
A = 1631.6871516 in²
∴ Area of an Irregular Quadrilateral diagonal (e) = 7 in, diagonal(f) = 22 ft and degrees = 118 is 1631.6871516 in²
or
Unit Conversion of Length 7 in = 0.5833333 ft
7 Inches is 0.5833333 feet
To convert Inches to Feet
we know that, 1 Inches = 0.0833333 Feet or
1 Foot = 1/12 foot
To convert Inches to Feet, divide the inche value by 12.
Result in Foot: 7 × in/12 × ft/in
Cancel The Comman factor of in
Result in Feet: $7\above 1pt12$
Divide the 7 by 12
Result in Feet: 0.5833333 feet
∴ 7 Inches = 0.5833333 feet
A = 0.5833333 ft * ft ft * sin(1180)
Simplify the above equation
Area = 11.3311601 degrees²
∴ Area of an Irregular Quadrilateral diagonal (e) = 7 in, diagonal (f) = 22 ft with diagonal = 118 is [1631.6871516, 11.3311601] in²