Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : Jan 03, 2024


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Diagonal (e)
Diagonal (f)
Angle α


Area of an Irregular Quadrilateral diagonal (e) = 6 ft, diagonal(f) = 39 cm and radians = 0.5 is 3.6806293 ft2 or 3419.4163575 cm2.

Area of an Irregular Quadrilateral diagonal (e) = 6 ft, diagonal(f) = 39 cm and radians = 0.5 is 3.6806293 ft2 or 3419.4163575 cm2.


  Area of an Irregular Quadrilateral diagonal (e) = 6 ft, diagonal(f) = 39 cm and radians = 0.5 in other units

Value unit
0.0011219 km²
0.0006971 mi²
1.1218558
3.6806293 ft²
44.1675516 in²
1.2268764 yd²
112.1855811 cm²
1121.8558106 mm²

Steps:

Given that Irregular Quadrilateral diagonal (e) = 6 ft, diagonal(f) = 39 cm and radians = 0.5

We know that, Area = e * f * sin(α)

Put the values of e, f and α in above Area Formula

      Unit Conversion of Width 39 cm = 1.2795276 ft

39 Centimeters is 1.2795276 foot

To convert Centimeters to Feet

we know that, 1 Centimeter = 0.032809 Feet or
                         1 Centimeter = 1/30.48 Feet

To convert Centimeters to Foot, multiply the centimeter value by 30.84.

Result in Foot: 39 × cm/30.84 × ft/cm

Cancel The Comman factor of cm

Result in Foot: 39/30.84 ft

DIvide the 39 by 30.84

Result in Feet: 1.2795276 feet

∴ 39 Centimeters = 1.2795276 foot

A = 6 * 1.2795276 * sin(0.5)

Simplify the above equation

A = 3.6806293 ft²

∴ Area of an Irregular Quadrilateral diagonal (e) = 6 ft, diagonal(f) = 39 cm and radians = 0.5 is 3.6806293 ft²

or

      Unit Conversion of Length 6 ft = 182.88 cm

6 Foot is 182.88 Centimeters

To convert Foot to Centimeters

we know that, 1 Foot = 30.480 Centimeters

To convert Foot to Centimeters, multiply the foot value by 30.480

Result in Centimeters: 6 ft × 30.480 × cm/ft

Cancel The Comman factor of ft

Result in Centimeters: (6 x 30.480 cm)

Multiply 6 into 30.480

Result in Centimeters: 182.88 Centimeters

∴ 6 Foot = 182.88 Centimeters

A = 182.88 cm * 39 cm * sin(0.5)

Simplify the above equation

Area = 3419.4163575 cm²

∴ Area of an Irregular Quadrilateral diagonal (e) = 6 ft, diagonal (f) = 39 cm and radians = 0.5 is 3419.4163575 ft²