Area of an Irregular Quadrilateral Calculator
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Area of an Irregular Quadrilateral diagonal (e) = 40 ft, diagonal(f) = 54 in and radians = 0.3 is 53.1936372 ft2 or 7659.8837567 in2.
Area of an Irregular Quadrilateral diagonal (e) = 40 ft, diagonal(f) = 54 in and radians = 0.3 is 53.1936372 ft2 or 7659.8837567 in2.
Area of an Irregular Quadrilateral diagonal (e) = 40 ft, diagonal(f) = 54 in and radians = 0.3 in other units
| Value | unit |
|---|---|
| 0.0162134 | km² |
| 0.0100746 | mi² |
| 16.2134206 | m² |
| 53.1936372 | ft² |
| 638.3236464 | in² |
| 17.7312124 | yd² |
| 1621.3420619 | cm² |
| 16213.4206186 | mm² |
Steps:
Given that Irregular Quadrilateral diagonal (e) = 40 ft, diagonal(f) = 54 in and radians = 0.3
We know that, Area = e * f * sin(α)
Put the values of e, f and α in above Area Formula
Unit Conversion of Width 54 in = 4.5 ft
54 Inches is 4.5 feet
To convert Inches to Feet
we know that, 1 Inches = 0.0833333 Feet or
1 Foot = 1/12 foot
To convert Inches to Feet, divide the inche value by 12.
Result in Foot: 54 × in/12 × ft/in
Cancel The Comman factor of in
Result in Feet: $54\above 1pt12$
Divide the 54 by 12
Result in Feet: 4.5 feet
∴ 54 Inches = 4.5 feet
A = 40 * 4.5 * sin(0.3)
Simplify the above equation
A = 53.1936372 ft²
∴ Area of an Irregular Quadrilateral diagonal (e) = 40 ft, diagonal(f) = 54 in and radians = 0.3 is 53.1936372 ft²
or
Unit Conversion of Length 40 ft = 480.0 in
40 Foot is 480.0 inches
To convert Foot to Inches
we know that, 1 Foot = 12 inches
To convert Foot to inches, multiply the foot value by 12.
Result in Foot: 40 ft × 12 × in/ft
Cancel The Comman factor of ft
Result in Inches: (40 x 12 in)
Multiply 40 into 12
Result in Inches: 480.0 inches
∴ 40 Foot = 480.0 inches
A = 480.0 in * 54 in * sin(0.3)
Simplify the above equation
Area = 7659.8837567 in²
∴ Area of an Irregular Quadrilateral diagonal (e) = 40 ft, diagonal (f) = 54 in and radians = 0.3 is 7659.8837567 ft²