Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Angle (β)

Enter the Base (a)

Enter the Angle (γ)


Area of Triangle angle (β) 19 degrees, side 4 centimeters and with angle (γ) 154 degrees is 9.2746659 centimeters².

The area of a triangle is defined as the total space that is enclosed by any particular triangle. The basic formula to find the area of a given triangle is A = a² * sin(β) * sin(γ)/(2 * sin(β + γ)), where a is side, sin(β), sin(γ) are the angles of the given triangle. Area of Triangle angle (β) 19 degrees, side 4 centimeters and with angle (γ) 154 degrees is 9.2746659 centimeters².


    Area of a Triangle Angle(β) = 19 degrees by side(a) = 4 cm with angle(γ) = 154 degrees in other units

Value unit
9.275x 10-05 km2
5.763x 10-05 mi2
0.0927467 m2
0.3042869 ft2
3.6514433 in2
0.101429 yd2
9.2746659 cm2
92.746659 mm2

Steps:

Given that Angle (β) = 19 degrees , Side (a) = 4 cm and with Angle(γ) = 154 degrees

We Know that, Area = a² * sin(β) * sin(γ)/(2 * sin(β + γ))

Substitute the values of the angle (β) = 19 degrees , the side (a) = 4 cm , and the with angle (γ) = 154 degrees into the formula

4² * sin(cm) * sin(19)/(2 * sin(degrees + 154))

Simplify the above equations

A = 9.2746659 cm²

∴ Area of a Triangle angle (β) 19 degrees , side (b) 4 cm and with angle (γ) = 154 degrees is 9.2746659 cm²