Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Angle (β)

Enter the Base (a)

Enter the Angle (γ)


Area of Triangle angle (β) 0.9 radians, side 3 meters and with angle (γ) 33 degrees is 1.9276895 meters².

The area of a triangle is defined as the total space that is enclosed by any particular triangle. The basic formula to find the area of a given triangle is A = a² * sin(β) * sin(γ)/(2 * sin(β + γ)), where a is side, sin(β), sin(γ) are the angles of the given triangle. Area of Triangle angle (β) 0.9 radians, side 3 meters and with angle (γ) 33 degrees is 1.9276895 meters².


    Area of a Triangle Angle(β) = 0.9 radians by side(a) = 3 m with angle(γ) = 33 degrees in other units

Value unit
0.0019277 km2
0.0011978 mi2
1.9276895 m2
6.3244406 ft2
75.8932874 in2
2.1081469 yd2
192.76895 cm2
1927.6895 mm2

Steps:

Given that Angle (β) = 0.9 radians , Side (a) = 3 m and with Angle(γ) = 33 degrees

We Know that, Area = a² * sin(β) * sin(γ)/(2 * sin(β + γ))

Substitute the values of the angle (β) = 0.9 radians , the side (a) = 3 m , and the with angle (γ) = 33 degrees into the formula

3² * sin(m) * sin(0.9)/(2 * sin(radians + 33))

Simplify the above equations

A = 1.9276895 m²

∴ Area of a Triangle angle (β) 0.9 radians , side (b) 3 m and with angle (γ) = 33 degrees is 1.9276895 m²