Area of a Triangle Angle(β) = 51 degrees by side(a) = 15 in with angle(γ) = 101 degrees Calculator
Area of Triangle angle (β) 51 degrees, side 15 inches and with angle (γ) 101 degrees is 182.3107027 inches².
The area of a triangle is defined as the total space that is enclosed by any particular triangle. The basic formula to find the area of a given triangle is A = a² * sin(β) * sin(γ)/(2 * sin(β + γ)), where a is side, sin(β), sin(γ) are the angles of the given triangle. Area of Triangle angle (β) 51 degrees, side 15 inches and with angle (γ) 101 degrees is 182.3107027 inches².
Area of a Triangle Angle(β) = 51 degrees by side(a) = 15 in with angle(γ) = 101 degrees in other units
| Value | unit |
|---|---|
| 0.0046307 | km2 |
| 0.0028774 | mi2 |
| 4.6306918 | m2 |
| 15.1925586 | ft2 |
| 182.3107027 | in2 |
| 5.0641862 | yd2 |
| 463.0691849 | cm2 |
| 4630.6918486 | mm2 |
Steps:
Given that Angle (β) = 51 degrees , Side (a) = 15 in and with Angle(γ) = 101 degrees
We Know that, Area = a² * sin(β) * sin(γ)/(2 * sin(β + γ))
Substitute the values of the angle (β) = 51 degrees , the side (a) = 15 in , and the with angle (γ) = 101 degrees into the formula
15² * sin(in) * sin(51)/(2 * sin(degrees + 101))
Simplify the above equations
A = 182.3107027 in²
∴ Area of a Triangle angle (β) 51 degrees , side (b) 15 in and with angle (γ) = 101 degrees is 182.3107027 in²