Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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Diagonal (e)
Diagonal (f)


Area of a Rhombus Diagonal-e 6 in and Diagonal-f 9 m is 1062.99 in2 or 0.6858 m2.

Area of a Rhombus Diagonal-e 6 in and Diagonal-f 9 m is 1062.99 in2 or 0.6858 m2.


  Area of a Rhombus Diagonal-e 6 in and Diagonal-f 9 m in other units

Value unit
0.0269999 km²
0.016777 mi²
26.999946
88.5825 ft²
1062.99 in²
29.5275 yd²
2699.9946 cm²
26999.946 mm²

Steps:

Given that Rhombus Diagonal (e) = 6 in and Diagonal (f) = 9 m

We know that, Area = (e * f)/2

      Unit Conversion of Width 9 m = 354.33 in

9 meter is 354.33 inches

To convert Meters to Inches

we know that, 1 Meter = 39.37 Inch

To convert meter to Inch,multiply the meter value by 39.37.

Result in Inches: 9 m × 39.37 × in/m

Cancel The Comman factor of m

Result in Inches: (9 * 39.37 in)

Multiply 354.33 into 39.37

∴ 9 meter = 354.33 inches

Put the values e, f values in above Area Formula

A = (6 * 354.33)/2

Simplify the above Equations

A = 1062.99 in²

∴ Area of a Rhombus diagonal-e 6 in and diagonal-f 9 m is 1062.99 in²

or

      Unit Conversion of Length 6 in = 0.1524 m

6 inches is 0.1524 meters

To convert inches to meter

we know that, 1 inch = 0.0254 meters

To convert inches to meter,multiply the inches value by 0.0254.

Result in Inches: 6 in x 0.0254 × m/in

Cancel The Comman factor of m

Result in Meters: (6 x 0.0254 m)

Multiply 6 into 0.0254

Result in meters: 0.1524 meters

∴ 6 inches = 0.1524 meters

Put the values e, f values in above Area Formula

A = (0.1524 * 9)/2

Simplify the above Equations

A = 0.6858 m²

∴ Area of a Rhombus diagonal-e 6 in and diagonal-f 9 m is 0.6858 m²