Area of a Regular Octagon side 5 in Calculator
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Area of a Regular Octagon side 5 in is 120.7106781 in²
Area of a Regular Octagon side 5 in is 120.7106781 in²
Area of a Regular Octagon side 5 in in other units
| Value | unit |
|---|---|
| 0.0030661 | km² |
| 0.0019052 | mi² |
| 3.0660512 | m² |
| 10.0592232 | ft² |
| 120.7106781 | in² |
| 3.3530744 | yd² |
| 306.6051224 | cm² |
| 3066.0512237 | mm² |
Steps:
Given that Side, a = 5 in
We know that, Area = 2 (1 + √2) * a²
Put the value of side in area Formula.
A = 2 (1 + √2) * 5²
Simplify the above equation
A = 120.7106781 in²
∴ Area of a Regular Octagon side 5 in is 120.7106781 in²