# Area of a Regular Octagon side 5 ft Calculator

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## Area of a Regular Octagon side 5 ft is 120.7106781 ft²

Area of a Regular Octagon side 5 ft is 120.7106781 ft²

## Area of a Regular Octagon side 5 ft in other units

Value | unit |
---|---|

0.0367926 | km² |

0.0228619 | mi² |

36.7926147 | m² |

120.7106781 | ft² |

1448.5281372 | in² |

40.2368927 | yd² |

3679.2614685 | cm² |

36792.6146849 | mm² |

**Steps:**

Given that Side, a = 5 ft

We know that, **Area = 2 (1 + √2) * a²**

Put the value of side in area Formula.

A = 2 (1 + √2) * 5²

Simplify the above equation

A = 120.7106781 ft²

∴ Area of a Regular Octagon side 5 ft is 120.7106781 ft²